147.对链表进行插入排序
小于 1 分钟
147.对链表进行插入排序
/*
* @lc app=leetcode.cn id=147 lang=typescript
*
* [147] 对链表进行插入排序
*/
// @lc code=start
/**
* Definition for singly-linked list.
* class ListNode {
* val: number
* next: ListNode | null
* constructor(val?: number, next?: ListNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
* }
*/
class ListNode {
val: number;
next: ListNode | null;
constructor(val?: number, next?: ListNode | null) {
this.val = val === undefined ? 0 : val;
this.next = next === undefined ? null : next;
}
}
function insertionSortList(head: ListNode | null): ListNode | null {
if (!head || !head.next) return head;
let dummy = new ListNode(0); // 创建一个哑节点作为排序链表的头
dummy.next = head;
let current: ListNode | null = head.next;
head.next = null; // 开始时,已排序链表只有一个元素(即原来的头节点)
while (current) {
let next: ListNode | null = current.next; // 保存下一个待排序节点
let prev = dummy;
// 在已排序链表中找到正确的插入位置
while (prev.next && prev.next.val < current.val) {
prev = prev.next;
}
// 插入当前节点
current.next = prev.next;
prev.next = current;
current = next; // 继续处理下一个待排序节点
}
console.log(dummy);
return dummy.next; // 返回排序后的链表头
}
let tag1 = new ListNode(4);
let tag2 = new ListNode(2);
let tag3 = new ListNode(1);
let tag4 = new ListNode(3);
tag1.next = tag2;
tag2.next = tag3;
tag3.next = tag4;
insertionSortList(tag1);
// console.log(insertionSortList(tag1));
// @lc code=end
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